This should help you here are the steps of your problem :)
2*(1/2)*r+2*r+1 = 9*(1/10) // - 9*(1/10)
2*(1/2)*r+2*r-(9*(1/10))+1 = 0
2*(1/2)*r+2*r-9/10+1 = 0
3*r+1/10 = 0 // - 1/10
3*r = -1/10 // : 3
r = -1/10/3
r = -1/30
r = -1/30
So your answer would be 1/30
Answer:
3.84% probability that it has a low birth weight
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
If we randomly select a baby, what is the probability that it has a low birth weight?
This is the pvalue of Z when X = 2500. So
has a pvalue of 0.0384
3.84% probability that it has a low birth weight
The answer to your question is b. 2
i think its -3
hope its right and helpful
if it is then mark brainlyist