2 years ago

ST has endpoints S(-2,-4) and T(6,8). Find the coordinates of the midpoint of ST.

Mathematics

1 answer:

Ierofanga [76]2 years ago

5 0

The midpoint is (2,2)

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Pls answer the question in the picture.

mr_godi [17]

Answer:

5:2

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Solve the following quadratic equation. (x+12)^2=1 A. x = 11 and x = 13 B. x = -11 and x = -13 C. x = -11 and x = 13 D. x = 11 a

sveticcg [70]

Answer:

Step-by-step explanation:

(x+12)^2=1

(x+12)= +or - 1

when

x+12=1

x=1-12 =-11

when

x+12=-1

x=-1-12 =-13

then

x=-11 and x= -13

7 0

2 years ago

Evaluate $\dfrac{2\sqrt{72}}{\sqrt{8}+\sqrt{2}}$.

Pavlova-9 [17]

<h3>Answer: 4</h3>

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Work Shown:

$\frac{2\sqrt{72}}{\sqrt{8}+\sqrt{2}}\\\\\frac{2\sqrt{36*2}}{\sqrt{4*2}+\sqrt{2}}\\\\\frac{2\sqrt{36}*\sqrt{2}}{\sqrt{4}*\sqrt{2}+\sqrt{2}}\\\\\frac{2*6*\sqrt{2}}{2*\sqrt{2}+\sqrt{2}}\\\\\frac{12\sqrt{2}}{2\sqrt{2}+\sqrt{2}}\\\\\frac{12\sqrt{2}}{3\sqrt{2}}\\\\\frac{12}{3}\\\\4$

Note in step 2, I factored each number in the square root to pull out the largest perfect square factor. From there, I used the rule that $\sqrt{A*B} = \sqrt{A}*\sqrt{B}$ to break up the roots.