Answer:
Step-by-step explanation:
As per Janayda,
From the figure attached,
In ΔTRQ,
m∠TRQ + m∠RQT + m∠QTR = 180°
25° + m∠RQT + 35° = 180°
m∠RQT = 180° - 60°
m∠RQT = 120°
Since, m∠RQT + m∠PQT = 180° [Linear pair of angles]
m∠PQT = 180° - m∠RQT
= 180° - 120°
= 60°
In right angled triangle TPQ,
m∠TPQ + m∠PQT + m∠PTQ = 180°
90° + 60° + m∠PTQ = 180°
m∠PTQ = 180° - 150°
= 30°
Similarly, other angles can also be evaluated from the given information.
In ΔQTP and ΔNTP,
TP ≅ TP [Reflexive property]
NP ≅ PQ [Given]
ΔQTP ≅ ΔNTP [By LL postulate for congruence]
Therefore, Janayda is correct.
While Sirr is incorrect.
Since, there is not the enough information to prove ΔRTQ and ΔMTN equal, Isabelle is incorrect.
The answer is 145 mansnjsjejsjjsjsjejejejejejejdjuehdybe
Answer:
The graph is attached below.
Step-by-step explanation:
The volume of the box containing the coffee mugs is,
Then the function representing the side length, in inches, for the box is:
Now, it is provided that the company decides to double the volume of the box.
That is, the new volume will be:
Then the side length, in inches, for the box will be:
![g_{n}(x)=\sqrt[3]{2x^{3}} =\sqrt[3]{2}x](https://tex.z-dn.net/?f=g_%7Bn%7D%28x%29%3D%5Csqrt%5B3%5D%7B2x%5E%7B3%7D%7D%20%3D%5Csqrt%5B3%5D%7B2%7Dx)
Then the graph representing the function, formed using the following points is:
Answer:
0.94$
Step-by-step explanation:
