The freezing point depression is calculated through the equation,
ΔT = (kf) x m
where ΔT is the difference in temperature, kf is the freezing point depression constant (1.86°C/m), and m is the molality. Substituting the known values,
5.88 = (1.86)(m)
m is equal to 3.16m
Recall that molality is calculated through the equation,
molality = number of mols / kg of solvent
number of mols = (3.16)(1.25) = 3.95 moles
Then, we multiply the calculated amount in moles with the molar mass of ethylene glycol and the answer would be 244.9 g.
Answer:
2.30 × 10⁻⁶ M
Explanation:
Step 1: Given data
Concentration of Mg²⁺ ([Mg²⁺]): 0.039 M
Solubility product constant of Mg(OH)₂ (Ksp): 2.06 × 10⁻¹³
Step 2: Write the reaction for the solution of Mg(OH)₂
Mg(OH)₂(s) ⇄ Mg²⁺(aq) + 2 OH⁻(aq)
Step 3: Calculate the minimum [OH⁻] required to trigger the precipitation of Mg²⁺ as Mg(OH)₂
We will use the following expression.
Ksp = 2.06 × 10⁻¹³ = [Mg²⁺] × [OH⁻]²
[OH⁻] = 2.30 × 10⁻⁶ M
The answer to this would be helium
The balanced dissociation equation for Cs₂CO₃ is:
Cs₂CO₃(aq) —> Cs⁺(aq) + CO₃²¯(aq)
A dissociation equation is an equation showing the available ions present in a solution.
To obtain the dissociation equation, the compound must be dissolved in water to produce an aqueous solution.
The dissociation equation for Cs₂CO₃ can be written as follow
Cs₂CO₃(aq) —> Cs⁺(aq) + CO₃²¯(aq)
Learn more about dissociation equation: brainly.com/question/1903354
The mass of 8 mol of ¹²C is 96 g.
Mass = 8 mol × (12 g/1 mol) = 96 g
