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3 years ago

Write 2 subtraction equations to show how to find 15-7

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

6 0

So 15-7 is 8

Here are some things I did:

10-2 or 28-20

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$\frac{1}{11}$

Step-by-step explanation:

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PLEASE HELP WILL GIVE BRAINLIEST! What is the following sum? Assume x > or equal to 0 and y is > or equal to 0.

Ira Lisetskai [31]

Answer:

Option (b) is correct.

The sum of given expression $\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$ is $2xy\sqrt{y}+2xy^2\sqrt{x}$

Step-by-step explanation:

Given:Expression $\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$

We have to find the sum of the given expression and choose the correct from the given options.

Consider the given expression $\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$ .

$\sqrt{x^2y^3}$ can be written as $\sqrt{x^2y^2y}=xy\sqrt{y}$

Also, $2\sqrt{x^3y^4}$ can be written as $2\sqrt{x^3y^4}=2\sqrt{x^2x(y^2)^2}=2xy^2\sqrt{x}$

Now, the given expression becomes,

$\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$

$=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}$ .

Now, adding like term, terms having same variable with same degree.

$=2xy\sqrt{y}+2xy^2\sqrt{x}$ .

Thus, The sum of given expression $\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$ is $2xy\sqrt{y}+2xy^2\sqrt{x}$

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2 years ago