Let us say T= probability of head turning up = 1/2 in one toss
H = probability of a tail turning up = 1/2 in one toss
Then P (56 heads or more) =
1/2^100 [ C(100,56) + C(100,57) + C(100,58) + ....
C(100,98) + C(100,99) + C(100,100) ]
where C(N, R) = N ! / [ (N - R)! R! ] number of occurrances of R formed from
N tosses.
This is a trick question. the answer is neither, they are both equivalent to one another :)
Answer:
15
Step-by-step explanation:
When you multiply 6 by 600 it equals 3,600
6x600=3,600
1 apple + 1 banana
1 apple + 1 orange
1 apple + 1 peach
1 banana + 1 apple
1 banana + 1 orange
1 banana + 1 peach
1 orange + 1 apple
1 orange + 1 banana
1 orange + 1 peach
1 peach + 1 apple
1 peach + 1 orange
11 combinations of food
Hope this helped