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2 years ago

What is a stable and radioactive isotopes

1 answer:

4 0

All elements with atomic numbers greater than 83 areradioisotopes meaning that these elements haveunstable nuclei and are radioactive. Elements with atomic numbers of 83 and less, have isotopes (stablenucleus) and most have at least one radioisotope (unstable nucleus).

A Radioisotope is also an isotope by nature. The difference is that radioisotopes are very unstable and contain high levels of nuclear energy and emit this energy in the form of nuclear radiation. Main difference: Isotopes can be stable or unstable, but Radioisotopes are always unstable.

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Solve for y in the following problem: 5.3 x 10- (y)(2y)

weqwewe [10]

Answer:

The value of y = 5.1478

Explanation:

The linear equation is an equation obtained when a linear polynomial is equated to zero. When the solution obtained on solving the equation is substituted in the equation in place of the unknown, the equation gets satisfied.

The given equation: 5.3 x 10- (y)(2y) = 0

⇒ 53 - 2y² = 0

⇒ 2y² = 53

⇒ y² = 53 ÷ 2 = 26.5

⇒ y = √26.5 = 5.1478

8 0

3 years ago

How many moles of NH3 can you make from 6.20 moles of N2?

german

4 I think

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4 0

2 years ago

Read 2 more answers

How is the food in a stomach broken down into simpler substances? What chemicals help this process?

Ksenya-84 [330]

Answer:

with the help of the juice contained in it

4 0

2 years ago

Sofia goes on a hike on a trail that is 10 km long. She starts at 2:00pm and ends at

Butoxors [25]

30 m/hrs (add me on discord if u have it Sipstic++#1460 )

8 0

2 years ago

Read 2 more answers

When 7.085 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 21.71 grams of CO2 and 10.37 grams of H

Taya2010 [7]

Answer:

- Empirical:

$C_3H_7$

- Molecular:

$C_6H_{14}$

Explanation:

Hello,

In this case, based on the information regarding the combustion, the moles of carbon turn out:

$n_C=21.71gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2}=0.493molC$

Moreover, the moles of hydrogen:

$n_H=10.37gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH}{1molH_2O}=1.152molH$

Thus, the subscripts of carbon and hydrogen in the hydrocarbon turn out:

$C=\frac{0.4934}{0.4934}=1\\H=\frac{1.15222}{0.4934}=2.335\\CH_{2.335}$

Now, looking for a suitable whole number we obtain the following empirical formula as 2.335 times 3 is 7 for hydrogen:

$C_3H_7$

In such a way, that compound has a molar mass of 43 g/mol, thus, the whole compound's molar mass is 86.18 g/mol for which the molecular formula is twice the empirical one, therefore:

$C_6H_{14}$

Which is hexane.

Best regards.

6 0

2 years ago