Answer:
The magnitude of the acceleration of the tip of the minute hand of the clock .
Explanation:
Given that,
Length of minute hand = 0.55 m
Length of hour hand = 0.26 m
The time taken by the minute hand to complete one revelation is
We need to calculate the angular frequency
Using formula of angular frequency
Put the value into the formula
We need to calculate the magnitude of the acceleration of the tip of the minute hand of the clock
Using formula of acceleration
Put the value into the formula
Hence, The magnitude of the acceleration of the tip of the minute hand of the clock .
Answer:
0.6
Explanation:
Angular acceleration is equal to Net Torque divided by rotational inertia, which is the rotational equivalent to Newton’s 2nd Law. Therefore, angular acceleration is equal to 3.6/6 which is 0.6. Hope this helped!
Answer:
The magnitude of momentum of the airplane is .
Explanation:
Given that,
Mass of the airplane, m = 3400 kg
Speed of the airplane, v = 450 miles per hour
Since, 1 mile per hour = 0.44704 m/s
v = 201.16 m/s
We need to find the magnitude of momentum of the airplane. It is given by the product of mas and velocity such that,
or
So, the magnitude of momentum of the airplane is . Hence, this is the required solution.