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2 years ago

8

Joana's printer can print 96 black and white pages in 4 minutes. If the ratio of pages printed to minutes is constant, how many

minutes will it take the printer to print 240 pages

1 answer:

nalin [4]2 years ago

5 0

Answer:

10 minutes

Step-by-step explanation:

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1cm 8cm 4cm: surface area

valkas [14]

Answer:

Perimeter of Triangle sum of all sides.

=13 cm

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2 years ago

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For each level of precision, find the required sample size to estimate the mean starting salary for a new CPA with 95 percent co

Rzqust [24]

Answer:

(a) Margin of error ( E) = $2,000 , n = 54

(b) Margin of error ( E) = $1,000 , n = 216

(c) Margin of error ( E) = $500 , n= 864

Step-by-step explanation:

Given -

Standard deviation $\sigma$ = $7,500

$\alpha$ = 1 - confidence interval = 1 - .95 = .05

$Z_{\frac{\alpha}{2}}$ = $Z_{\frac{.05}{2}}$ = 1.96

let sample size is n

(a) Margin of error ( E) = $2,000

Margin of error ( E) = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

E = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$E^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{2000^{2}} \times 7500^{2}$

n = 54.0225

n = 54 ( approximately)

(b) Margin of error ( E) = $1,000

E = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

1000 = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$1000^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{1000^{2}} \times 7500^{2}$

n = 216

(c) Margin of error ( E) = $500

E = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

500 = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$500^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{500^{2}} \times 7500^{2}$

n = 864

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2 years ago

Please Answer this question 15 points

WINSTONCH [101]

Answer:

btw it olny 8 points but it is c

Step-by-step explanation:

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2 years ago

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An assembly line with 10 tasks needs be designed. The total time for all tasks is 16 minutes. If you need to produce 30 units/ho

Sindrei [870]

Answer: 8 minimum work stations is what would be needed.

Step-by-step explanation:

The cycle time is computed as the operating time daily divided by the scheduled output.

It is important to note that the daily capacity of the operation layout is the operating time divided by the cycle time.

Therefore,

If you need to produce 30units/hour.

The average cycle time is as follow:

The average cycle time is the average time between the completions of units.

60/30= 2 average cycle time

=16/2

=8

8 work stations is the minimum number that would be needed.

It is important to know that in an assembly line balancing, the minimum number of work station is the ratio of the sum of all tasks time to the cycle time.

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2 years ago

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aleksandrvk [35]

Answer:

Step-by-step explanation:

yes

yes because its a decimal and positive

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2 years ago