Is there a graph or something?
Answer:
Step-by-step explanation:
surface area of one can 2πrh+2πr²
=2πr(h+r)
≈2×3.14×3/2(4.25+1.5)
≈9.42(5.75)
≈54.165 in²
number of cans=1000/54.165
=18 cans
material used=18×54.165≈975 in²
material left=1000-975=25 in²
For this case we can solve the problem by means of the following rule of three:
94 --------> 100%
17 --------> x
Clearing x we have:
x = (17/94) * (100)
x = 18,08510638%
To the nearest tenth of a percent:
x = 18.1%
Answer:
This is 18.1% of his compact discs.
Answer:
Step-by-step explanation:
The complete question is
Water flows into a tank according to the rate F(t)= (t+6)/(1+t), and at the same time empties out at the rate E(t)= (ln(t+2))/(t+1), with both F(t) and E(t) measured in gallons per minute. How much water, to the nearest galllon, is in the tank at time t=10 minutes.
Let C(t) be the amount of water in the tank at time t. We now that the rate of change of the tank is given by
Unfortunately, the integral cannot be expressed using fundamental functions. So, the problem cannot have an specific function (if you are willing to know the complete answer, the integral of this function uses the polylogarithm function with n=2).
Since you want the exact amount of water at time, you need to give C a value, that is, you need to know an initial condition for the problem. This means, you need to know the amount of water in the tank at time 0
<h2><u>Question</u>:-</h2>
Find the volume of a cylinder with a radius of 3 meters and a height of 13 meters.
<h2><u>Answer</u>:-</h2>
<h3>Given:-</h3>
Radius (r) of a cylinder = 3 meters.
Height (h) of a cylinder = 13 meters.
<h3>To Find:-</h3>
The volume of a cylinder.
<h2>Solution:-</h2>
We know,
Formula of Volume of a cylinder is πr²h.
So, Volume of a cylinder = 3.14 × (3)² × 13
Volume of a cylinder = 3.14 × 3 × 3 × 13
Volume of a cylinder = 367.38 cubic meters.
<h3>The volume of a cylinder is <u>3</u><u>6</u><u>7</u><u>.</u><u>3</u><u>8</u><u> </u><u>cubic </u><u>meters</u>. [Answer]</h3>