Given the angle:
-660°
Let's find the coterminal angle from 0≤θ≤360.
To find the coterminal angle, in the interval given, let's keep adding 360 degrees to the angle until we get the angle in the interval,
We have:
Coterminal angle = -660 + 360 = -300 + 360 = 60°
Therefore, the coterminal angle is 60°.
Since 60 degrees is between 0 to 90 degrees, is is quadrant I.
60 degrees lie in Quadrant I.
Also since it is in quadrant I, the reference angle is still 60 degrees.
ANSWER:
The coterminal angle is 60°, which lies in quadrant I, with a reference angle of 60°
9514 1404 393
Answer:
59°
Step-by-step explanation:
Opposite angles of an inscribed quadrilateral are supplementary.
∠N +∠L = 180°
(a +16) +(a -18) = 180
2a = 182 . . . . . . . . . . add 2
a = 91 . . . . . . . . . . . . divide by 2
Then the measure of angle M is ...
∠M = (a+30)° = (91 +30)° = 121°
and angle K is its supplement.
∠K = 180° -121°
∠K = 59°
Answer:
Step-by-step explanation:
26% is (26-20)/(50-20) = 6/30 = 1/5 of the way between 20% and 50%. That means 1/5 of the solution is 50% acid.
50% acid: 1/5 · 100 mL = 20 mL
20% acid: 100 mL -20 mL = 80 mL
Delbert must mix 80 mL of 20% acid and 20 mL of 50% acid.
_____
Maybe you'd like to see an equation. Let x represent the amount of 50% acid required. Then 100-x is the amount of 20% acid needed. The amount of acid in the mix is ...
0.50(x) +0.20(100 -x) = 0.26(100)
(0.50 -0.20)x = (0.26 -0.20)100 . . . . subtract 0.20(100)
x = (0.26 -0.20)/(0.50 -0.20)×100 = 20
This last expression should look a lot like the one we started with in this answer. It shows you how you can almost write down the answer to mixture problems without a lot of work.
