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2 years ago

Landon wrote that 3−2.6=4. Which statement about his answer is true?

Mathematics

1 answer:

max2010maxim [7]2 years ago

4 0

Answer:

Without place values or decimals, this answer is correct numerically, but once you add those in, you find that the answer is actually 0.4

Step-by-step explanation:

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The top and bottom margins of a poster are each 15 cm and the side margins are each 10 cm. If the area of printed material on th

12345 [234]

Answer:

the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.

Step-by-step explanation:

From the given question.

Let p be the length of the of the printed material

Let q be the width of the of the printed material

Therefore pq = 2400 cm ²

q = $\dfrac{2400 \ cm^2}{p}$

To find the dimensions of the poster; we have:

the length of the poster to be p+30 and the width to be $\dfrac{2400 \ cm^2}{p} + 20$

The area of the printed material can now be: $A = (p+30)(\dfrac{2400 }{p} + 20)$

= $2400 +20 p +\dfrac{72000}{p}+600$

Let differentiate with respect to p; we have

$\dfrac{dA}{dp}= 20 - \dfrac{72000}{p^3}$

Also;

$\dfrac{d^2A}{dp^2}= \dfrac{144000}{p^3}$

For the smallest area $\dfrac{dA}{dp }=0$

$20 - \dfrac{72000}{p^2}=0$

$p^2 = \dfrac{72000}{20}$

p² = 3600

p =√3600

p = 60

Since p = 60 ; replace p = 60 in the expression q = $\dfrac{2400 \ cm^2}{p}$ to solve for q;

q = $\dfrac{2400 \ cm^2}{p}$

q = $\dfrac{2400 \ cm^2}{60}$

q = 40

Thus; the printed material has the length of 60 cm and the width of 40cm

the length of the poster = p+30 = 60 +30 = 90 cm

the width of the poster = $\dfrac{2400 \ cm^2}{p} + 20$ = $\dfrac{2400 \ cm^2}{60} + 20$ = 40 + 20 = 60

Hence; the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.

4 0

2 years ago

Terrence finished a word search in 3/4 the time it took frank. charlotte finished the word search in 2/3 the time it took terren

Luden [163]

Answer:

Charlotte-16

Step-by-step explanation:

In order to calculate the time that Charlotte took we just first have to calculate the time that Terrence took to finish the word search, that is done by multiplying the 32 minutes that Frank took by the three quartes that it took terrence:

$Time=(\frac{3}{4}) (32)\\Time=(\frac{96}{4})\\Time=24$

So now we know that It took terrence 24 minutes, and that Charlotte took two thirds of that time so we now just multiply that:

$Time=(\frac{2}{3}) (24)\\Time=(\frac{48}{3})\\Time=16$

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Measures of variability,i have learned that

Svetllana [295]

Answer:

Measures of Variability: Range, Interquartile Range, Variance, and Standard Deviation. ... While a measure of central tendency describes the typical value, measures of variability define how far away the data points tend to fall from the center. We talk about variability in the context of a distribution of values.

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2 years ago

Which best describes the dna of a cloned animal

pychu [463]

I think it has the same DNA as its parent

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AYUDA CON ESTO!!! ALGUIEN PORFAVOR

Gre4nikov [31]

Answer:

Problem 1) frequency: 160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)