Please help help me please

2 intersecting lines are shown. A line with point T, R, W intersects a line with points S, R, V at point R. Clockwise, from the

Mademuasel [1]

Answer:

The measure of angle TRV is 130° ⇒ last answer

Step-by-step explanation:

* <em>According to the attached graph</em>

- Line TRW intersects line SRV at point R

- The measure of angle VRT is (2x + 10)°

- The measure of angle VRW is (x - 10)°

- We need to find measure of angle TRV

- <em>From the attached figure</em>

∵ T , R , W lie on the same line

∴ ∠TRW is a straight angle

- The measure of the straight angle is 180°

∴ m∠TRW = 180°

∵ ∠TRW contains ∠VRT and ∠VRW

∴ m∠VRT + m∠VRW = m∠TRW

∴ m∠VRT + m∠VRW = 180°

∵ m∠VRT = (2x + 10)°

∵ m∠VRW is (x - 10)°

∴ 2x + 10 + x - 10 = 180

- Add like terms

∴ 3x = 180

- Divide both sides by 3

∴ x = 60

∵ m∠TRV = (2x + 10)°

- Substitute x by 60

∴ m∠TRV = 2(60) + 10 = 120 + 10 = 130°

∴ The measure of angle TRV is 130°

5 0

2 years ago

Read 2 more answers

The monthly worldwide average number of airplane crashes of commercial airlines is 2.2. What is the probability that there will

Makovka662 [10]

Answer:

(a) more than 2 such accidents in the next month $\approx 0.3773$

(b) more than 4 such accidents in the next 2 months $\approx 0.44882$

(c) more than 5 such accidents in the next 3 more than 5 such accidents in the next 3 months $\approx 0.64533$

Step-by-step explanation:

Let N be the Random variable that marks the number of crashes in certain month.

Now let us use Poisson distribution since we are given with average number of crashes that is N \sim Pois(2.2)

(A) more than 2 such accidents in the next month

Probability(more than 2 such accidents in the next month)=P(N>2)

P(N>2)=1-P(N=0)-P(N=1)-P(N=2)

=> $1-e^-{2.2}-2.2e^{-2.2}-\frac{2.2^2}{2!}e^{2.2}$

=> $\approx 0.3773$

B) more than 4 such accidents in the next 2 months

since the average number of crashes in 1 month is 2.2, the average number of crashes in two months is 4.4. hence, if we say that $N_1$ is the number of crashes in 2 months, we have that $N\sim$ Pois(4.4)

Thus,

Probability(more than 4 such accidents in the next 2 months)=P( $N_1>4$ )

= $1-P(N_1=0)-P(N_1=1)-P(N_1=2)=P(N_1=3)-P(N_1=4)$

$1-\sum_{k=1}^{4} \frac{4.4^{k}}{k !} e^{-4.4}$

=> $\approx 0.44882$

C) more than 5 such accidents in the next 3 more than 5 such accidents in the next 3 months

If we say that $N_2$ marks the number of crashes in the next 3 months , using the same argument as in (a) we have that a $N\sim$ Pois(6.6)

Hence

P( $N_2>5$ )= $1-\sum_{k=0}^{5} \frac{6.6^{k}}{k !} e^{-6.6}$

=> $\approx 0.64533$

6 0

2 years ago

Can anybody help me on Simplying expressions w/ rational numbers??

bezimeni [28]

Answer: $1-\frac{9}{7}n$

Step-by-step explanation:

You need to remember the multiplication of signs:

$(+)(+)=+\\(-)(-)=+\\(-)(+)=-\\(-)(+)=-$

And the the Distributive property. This states that:

$c(a\±b)=ac\±bc$

In this case, given the following expression:

$\frac{1}{7}-3(\frac{3}{7}n-\frac{2}{7})$

In order to to create an equivalent expression, the first step is to apply the Distributive property. Then:

$\frac{1}{7}-\frac{3*3}{7}n+\frac{2*3}{7}\\\\\frac{1}{7}-\frac{9}{7}n+\frac{6}{7}$

You can identify that the like terms are:

$\frac{1}{7}$ and $\frac{6}{7}$

So, you can combine these like terms. This means that you must add them. Since both terms have equal denominator, you need to rewrite the denominator and just add the numerators.

Then, you get:

$\frac{1+6}{7}-\frac{9}{7}n=\frac{7}{7}-\frac{9}{7}n=1-\frac{9}{7}n$

8 0

2 years ago

-3+ 4d - 2f + 3d + 6f - 4 - 8

Igoryamba

Answer:

Explanation:

-3 + 4d - 2f + 3d + 6f - 4 - 8

= −3 + 4d + −2f + 3d + 6f + −4 + −8

Combine Like Terms

= −3 + 4d + −2f + 3d + 6f + −4 + −8

(4d + 3d) + (−2f + 6f) + (−3 + −4 + −8)

7d + 4f + −15

= 7d + 4f - 15

5 0

2 years ago

Banana Republic at the Orlando, Florida, outlet store sells casual jeans for $40 and dress jeans for $60. If customers bought 5

3241004551 [841]

Answer:

Banana Republic at the Orlando, Florida, outlet store sold 125 casual jeans and 25 Dress jeans last month.

Step-by-step explanation:

Given:

Cost of casual jeans = $40

Cost of Dress jeans = $60

Totaled amount of sales last month $6500

We need to find the number of casual jeans and number of dress jeans sold last month.

Solution:

Let the number of casual jeans sold be 'x'.

Also Let the number of dress jeans sold be 'y'.

Also Given:

If customers bought 5 times more casual than dress jeans last month.

So we can say that;

$x=5y \ \ \ \ equation \ 1$

Now we know that;

Totaled amount of sales last month is equal to the number of casual jeans sold multiplied by Cost of casual jeans plus the number of dress jeans sold multiplied by Cost of Dress jeans.

framing in equation form we get;

$40x+60y=6500 \ \ \ \ equation \ 2$