Answer:
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Answer:
some kind of chemical of which i do not know
Explanation:
Answer:
The kinetic energy of the mass at the instant it passes back through the equilibrium position is 0.06500 J.
Explanation:
Given that,
Mass = 2.15 kg
Distance = 0.0895 m
Amplitude = 0.0235 m
We need to calculate the spring constant
Using newton's second law
Where, f = restoring force
Put the value into the formula
We need to calculate the kinetic energy of the mass
Using formula of kinetic energy
Here,
Here,
Put the value into the formula
Hence, The kinetic energy of the mass at the instant it passes back through the equilibrium position is 0.06500 J.
The period T is time it takes for one complete cycle or from "trough to trough" so the reverse is trough per sec = 1/T = frequency
Answer:
10N
Explanation:
Equation: ΣF = ma
Fapp = ma
Fapp = (2kg)(5m/s^2) (im guessing you mean 5.00 m/s^2 not m/s)
Fapp = 10*kg*m/s^2
Fapp = 10N