Answer:
S varies partly directly as M and Q.
S=C.
S=KMQ+C.
For the first one...
speed=80,m=220,Q=30.
80=K20×30+C.
80=600K+C......(I).equation one.
For the second one....
speed=60,m=300,Q=40.
60=K300×40+C.
60=12000K+C.....(ii). equation two.
Minus eqtn(I) from eqtn(ii).
80=600K+C.
- 60=12000K+C.
K=0.01754~0.018.
Substitute K=0.018 into eqtn(I).
80=600K+C
80=600×0.018+C.
80=10.8+C.
C=80-10.8=69.2.
The relation is S=0.018MQ+69.2
when speed is 100 and mass is 250 find the volume.
100=0.018×250×Q+69.2.
100=4.5Q+69.2.
4.5Q=100-69.2
4.5Q=30.8.
Q=30.8/4.5.
Q=6.8~7litres.
Answer:
3+3+3x
i think idk just getting points goog luck
Step-by-step explanation:
Answer:
<em>The area of the shaded region is 3.</em>
Step-by-step explanation:
Since point E lies halfway between AB and BC, the area of the shaded region (As) consists of two identical triangles with base equal to AB and height equal to half the measure of BC:
Where At is the area of each triangle.
We know AB=3 and BC=2, thus:
Simplifying:
Finally:
The area of the shaded region is 3.
Note the area of the shaded region is half the area of the rectangle.
Answer:
60
Step-by-step explanation:
9 ÷ 15 = 0.6
Move decimal 2 places 0.6 -> 60
