Answer:
Density = Mass/volume. D= 60/30.Divide it and you'll get ur answer as 2
Answer:
The maximum electric power output is 
Explanation:
From the question we are told that
The capacity of the hydroelectric plant is 
The level at which water is been released is 
The efficiency is 
0.90
The electric power output is mathematically represented as
Where 
is the potential energy at level h which is mathematically evaluated as
and 
is the potential energy at ground level which is mathematically evaluated as
So
here 
where V is volume and 
is density of water whose value is 
So
substituting values
The maximum possible electric power output is
substituting values
Answer:
There will be two forces acting on her: Gravitational force and Air resisitence
Ur answer is 3 and i'm sure of it
The power of man performing 500 J of work in 8 seconds is 62.5 J/s.
Power can be defined as the pace at which work is completed in a given amount of time.
Horsepower is sometimes used to describe the power of motor vehicles and other machinery.
The pace at which work is done on an item is defined as its power. Power is a temporal quantity.
Which is connected to how quickly a project is completed.
The power formula is shown below.
Power = Energy / Time
Power = E / T
Because the standard metric unit for labour is the Joule and the standard metric unit for time is the second, the standard metric unit for power is a Joule / second, defined as a Watt and abbreviated W.
Here we have given Energy as 500 J and Time as 8 second.
Power = Energy / Time
Power = 500 / 8 Joule / sec
Power = 250 / 4 Joule / sec
Power = 125 / 2 Joule / sec
Power = 62.5 Joule / sec or 62.5 watt
Power came out to be 62.5 J/s when the man performed 500 Joule of work in 8 seconds.
So we can conclude that the power in the Energy transmitted per unit of time, and can be find out by dividing Energy by time. In our case the Power came out to be 62.5 Joule / Second.
Learn more about Power here:
brainly.com/question/1634438
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