Answer: $34
Step-by-step explanation: I took a test that had this question
Answer:
12(6)-12(k)
Step-by-step explanation:
No. A polynomial equation in one variablel ooks like P(x) = Q(x), where P and Q are polynomials.
Consider polynomial equations x^2 = 3 and x^2 = 1.
Obviously they have real solutions.
Subtract the two polynomial equations:
(x^2 - x^2) = (3 - 1)
0 = 2...
We get the polynomial equation 0 = 2. We call this a polynomial equation because single constants are also by definition polynomials.
Obviously 0 = 2 has no real solution.
<h2>
Explanation:</h2>
Hello, remember you need to write complete questions in order to get good and exact answers. Here you haven't provided any fractions, so I'll give you my own fractions.
The first fraction is:
The second fraction is:
So let's say that difference is:
Therefore, the result is:
The representation of this problem is shown using the number line below. As you can see, we have written both 1/2 and 1/4 and the difference is also indicated giving the result 1/4. That is, if we walk from 1/4 to 1/2 we'll walk 1/4 units.
Y+4=-2(x+1)
This is the point slope form (y-y1) =m(x-x1)
I hope it will helped!