A² - 225 = (a-15)(a+15)
..................................................................
3/8 = 0.375
40/0.375 = 106 and 2/3
Answer:
6°F
58°F
Step-by-step explanation:
From the data Given :
Temperature rise in Buffalo by noon time = 14°F
The initial temperature at Buffalo = - 8°F
Rise in temperature = 14°F
Therefore, temperature at noon = (-8 + 14)°F = 6°F
B.)
Temperature at 6am in St. Louis = 32°F
Temperature at 6am in Juneau = - 26°F
Temperature difference :
(32 - (-26))°F
32 + 26
= 58°F
Temperature in St. Louis is 58°F higher
(7-3+4^3/2) / (9-5)
7-3+64/2) / 4
(7-3 + 32) / 4
(4 + 32) / 4
36/4 = 9
48 + 72
24(2 + 3)
Lets make the graph of our systems of equations:
The blue line correspond to the equation x-y=3 and the red one correspond to 7x-y=-3. The lines intersect at point (-1,-4), then, the solution of the system is (-1,-4).
