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2 years ago

Find the samllest value of K when : 280k is a perfect square 882 is a cube

1 answer:

5 0

280 = 7 x 2^3 x 5
882 = 7^2 x 2 x 3^2

For 280k to be perfect square , their powers need to be even
For 882 to be a cube, their powers need to be in multiple of 3,

To satisfy both parties,
K = 7 x 2^5 x 3^4 x 5^3 = 2268000

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1000 grams decreased by 94%

gregori [183]

$subtract\ 94\%\ of\ 1000\ from\ 1000\\\\1000-94\%*10000=1000-0.94*1000=1000-940=60\\\\
1000\ grams\ decreased\ by\ 94\%\ is\ 60.$

3 0

2 years ago

Make sure u have explanation pls

Orlov [11]

Narrow
it describes a path lined with flowers

4 0

2 years ago

Stephanie surveyed the students in her class to find out their favorite color. her results are in the table. what percent of Ste

wariber [46]

Hi there!

To solve this problem, we need to find the amount of classmates out of the entire class who did not choose blue as their favorite color and then convert it into a percentage.

First, let's find the fraction:

Since there are 25 total people in her class, since

6 + 9 + 10 = 25

25 is the denominator of the fraction;

Since there are 16 people who did not choose blue,

6 + 10 = 16

16 is the numerator of the fraction.

So, our fraction is 16/25.

Now, we need to convert it into a percentage. To do this, we need to make the denominator 100 by multiplying it by a certain number, and then multiplying the numerator by that same number so the fraction stays equal:

16/25
= 16*4/25*4
= 64/100
= 64%

So, the answer is 64% of Stephanie's classmates.

Hope this helps!

3 0

2 years ago

Subtract and simplify. Show work please!

ra1l [238]

1) Final expression: $+7y^2-6y-17$

2) Final expression: $21x^3-46x^2+59x-30$

Step-by-step explanation:

The first expression is

$(-2y^2-11y-7)-(-9y^2-5y+10)$

First, we remove the 2nd bracket by changing the sign of all the terms inside:

$-2y^2-11y-7-+9y^2+5y-10$

Now we group the terms with same degree together:

$(-2y^2+9y^2)+(-11y+5y)+(-7-10)$

Now we solve the expression in each brackets:

$(-2y^2+9y^2)+(-11y+5y)+(-7-10)=\\+7y^2-6y-17$

So, this is the final expression.

The second expression is

$(7x-6)(3x^2-4x+5)$

We apply the distributive property, so we rewrite the expression as follows:

$(7x-6)(3x^2-4x+5)=7x(3x^2-4x+5)-6(3x^2-4x+5)$

Solving both brackets,

$7x(3x^2-4x+5)-6(3x^2-4x+5)=\\21x^3-28x^2+35x-18x^2+24x-30$

Now we group terms of same degree together:

$21x^3-28x^2+35x-18x^2+24x-30=\\21x^3+(-28x^2-18x^2)+(35x+24x)-30$

And solving each bracket,

$21x^3+(-28x^2-18x^2)+(35x+24x)-30=\\21x^3-46x^2+59x-30$

So, this is the final expression.

Learn how to simplify expressions:

brainly.com/question/7014769

brainly.com/question/11007572

brainly.com/question/11334714

#LearnwithBrainly

3 0

2 years ago

Does the frequency distribution appear to have a normal distribution using a strict interpretation of the relevant criteria?Tem

Xelga [282]

Answer:

B. No, this distribution does not appear to be normal

Step-by-step explanation:

Hello!

To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.

The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.

As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.

The answer is B.

I hope it helps!

3 0

2 years ago