Solve equation (2) for 'a' to get x+a = 2 a = 2-x Call this equation (3)
We will plug equation (3) into equation (1) x*a = 244 x*(a) = 244 x*(2-x) = 244 Notice how the 'a' is replaced with an expression in terms of x
Let's solve for x x*(2-x) = 244 2x-x^2 = 244 x^2-2x+244 = 0
If we use the discriminant formula, d = b^2 - 4ac, then we find that... d = b^2 - 4ac d = (-2)^2 - 4*1*244 d = -972 indicating that there are no real number solutions to the equation x^2-2x+244 = 0
So this means that 'x' and 'a' in those two original equations are non real numbers. If you haven't learned about complex numbers yet, then the answer is simply "no solution". At this point you would stop here.
If you have learned about complex numbers, then the solution set is approximately {x = 1 + 15.588i, a = 1 - 15.588i} which can be found through the quadratic formula
Note: it's possible that there's a typo somewhere in the problem that your teacher gave you.
If you have exited the country, you most likely took a plane. Therefore yes there is an association between having been on a airplane and visiting another country.
(Also do u go to CCA? Bc I had the same q on my math quiz in Mrs.Pfeiffer's class)
Mr. Hayes has 11 straw bundles to use forr bedding in his horse stalls. What is the greatest number of stalls he can fill if each stall holds exactly 4 bundles
1 stall = 4 bundles
4 bundles = 1 stall
11 bundles = x
Cross Multiply
4x = 11
x = 11/4
x = 2 3/4 stalls
The greatest number of stalls he can build is 2 stalls