Answer:
3.1 kg
Explanation:
Step 1: Write the balanced combustion equation
C₈H₁₈ + 12.5 O₂ ⇒ 8 CO₂ + 9 H₂O
Step 2: Calculate the moles corresponding to 1.0 kg of C₈H₁₈.
The molar mass of C₈H₁₈ is 114.23 g/mol.
1.0 × 10³ g × 1 mol/114.23 g = 8.8 mol
Step 3: Calculate the moles of CO₂ produced from 8.8 moles of C₈H₁₈
The molar ratio of C₈H₁₈ to CO₂ is 1:8. The moles of CO₂ produced are 8/1 × 8.8 mol = 70 mol.
Step 4: Calculate the mass corresponding to 70 moles of CO₂
The molar mass of CO₂ is 44.01 g/mol.
70 mol × 44.01 g/mol = 3.1 × 10³ g = 3.1 kg
Answer:
the error could have been the fact that the unit for volume wasn't changed from cm³ to dm³
hence the calculation error
the solution to this would be first dividing the volume by 1000 to get that same amount in dm³ which is the standard unit to be used for volume-density calculations
Answer:
330,000
Explanation:
Since there are only 2 significant figures in 0.024 ( and 0.024 is the number with the least number of significant numbers), the answer is 330,000, not 331,000.
<span>O2 travels slower than H2, Ne, N2, and CO. This is due to the fact that O2 has a heavier molecular weight than the others. O2 has a weight of 32 grams per mole. N2 and CO are the next highest with 28 grams per mole. Ne is 20 grams per mole, and H2 is 2 grams per mole.</span>
