2 years ago

What's (8,-2) (r,-6), m =-4

Mathematics

1 answer:

Troyanec [42]2 years ago

4 0

m is simply the slope of the line. The equation for m or slope is given as:

m = (y2 – y1) / (x2 – x1)

Therefore we can find for r by substituting the values:

- 4 = (-6 – (-2)) / (r – 8)

- 4 = - 4 / (r – 8)

r – 8 = 1

r = 9

So:

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Find the x-intercepts of the parabola with vertex (1,-108) and y-intercept (0,-105). Write your answer in this form: (X1,y1), (x

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Answer:

(7, 0) and (-5, 0)

Step-by-step explanation:

<u>Vertex form</u>

$y=a(x-h)^2+k$

(where (h, k) is the vertex)

Given:

vertex = (1, -108)

$\implies y=a(x-1)^2-108$

Given:

y-intercept = (0, -105)

$\implies a(0-1)^2-108=-105$

$\implies a(-1)^2=-105+108$

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Therefore:

$\implies y=3(x-1)^2-108$

The x-intercepts are when y = 0

$\implies 3(x-1)^2-108=0$

$\implies 3(x-1)^2=108$

$\implies (x-1)^2=36$

$\implies x-1=\pm \sqrt{36}$

$\implies x=1\pm 6$

$\implies x=7, x=-5$

Therefore, the x-intercepts are (7, 0) and (-5, 0)

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