1 answer:
Let x and y be your two consecutive whole numbers
x < sqrt(142) < y
x^2 < 142 < y
So, we are looking for x and y such that x^2 < 142 and y^2 > 142.
The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.
11 and 12 are consecutive.
11^2 = 121 < 142 < 144 = 12^2
Thus, 11 and 12 are your numbers
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9, -3
Step-by-step explanation:
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4x = 11 -3
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x =8/4
x =2
answer
the number is 2
3,500,000 - 2,800,000 = 700,000
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180 divided by 3 = 60
60 x 5 = 300
she can type 300 words in 5 minutes