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3 years ago

A farmer harvested a total of 364

Mathematics

1 answer:

defon3 years ago

8 0

Answer:

11 pounds and all together 4004

Step-by-step explanation:

hope its right hope it helps

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You and a friend or 2 pizzas from pizza hut. you ate 7/8 of one pizza and 3/4 of the other pizza. find the product of the amount

kotegsom [21]

13/8 or 1 5/8
3/4 becomes 7/8 when add it is 13/8

6 0

2 years ago

Please help! Which box plot represents a set of data that has the greatest mean absolute deviation? (see attached image)

djyliett [7]

Answer:

the 2nd is the answer

Step-by-step explanation:

7 0

2 years ago

Y = –3x 6 y = 9 what is the solution to the system of equations? (–21, 9) (9, –21) (–1, 9) (9, –1)

Romashka [77]

we have

The system of equations

$y=-3x+6$ -------> equation $1$

$y=9$ -------> equation $2$

Substitute equation $2$ in equation $1$

$9=-3x+6$

subtract $6$ both sides

$9-6=-3x+6-6$

$3=-3x$

Divide by $-3$ both sides

$x=-1$

the solution is the point $(-1,9)$

therefore

the answer is

the solution to the system of equations is the point $(-1,9)$

4 0

2 years ago

Read 2 more answers

Tan^2 A/1+cot^2 A + cot^2 A/1+tan^2 A=sec^2 A cosec^2 A-3

omeli [17]

$\frac{tan^2x}{1+cot^2x}+\frac{cot^2x}{1+tan^2x}=sec^2x\ cosec^2x-3\\\\L=\frac{tan^2x(1+tan^2x)+cot^2x(1+cot^2x)}{(1+cot^2x)(1+tan^2x)}=\frac{tan^2x+tan^4x+cot^2x+cot^4x}{1+tan^2x+cot^2x+tanxcotx}\\\\=\frac{tan^2x+cot^2x+tan^4x+cot^4x}{1+tan^2x+cot^2x+1}=\frac{tan^2x+2+cot^2x+tan^4x-2+cot^4x}{tan^2x+cot^2x+2}$

$=\frac{(tanx+cotx)^2+(tan^2x-cot^2x)^2}{(tanx+cotx)^2}=\frac{(tanx+cotx)^2}{(tanx+cotx)^2}+\frac{(tan^2x-cot^2x)^2}{(tanx+cotx)^2}\\\\=1+\frac{(tanx-cotx)^2(tanx+cotx)^2}{(tanx+cotx)^2}=1+(tanx-cotx)^2\\\\=1+tan^2x-2tanx\ cotx+cot^2x=tan^2x+cot^2x+1-2\\\\=\left(\frac{sinx}{cosx}\right)^2+\left(\frac{cosx}{sinx}\right)^2-1=\frac{sin^2x}{cos^2x}+\frac{cos^2x}{sin^2x}-1=\frac{sin^4x+cos^4x}{sin^2x\ cos^2x}-1$

$=\frac{(sin^2x)^2+2sin^2x\ cos^2x+(cos^2x)^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1\\\\=\frac{(sin^2x+cos^2x)^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1=\frac{1^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1\\\\=\frac{1}{sin^2x\ cos^2x}-\frac{2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1=\frac{1}{sin^2x}\cdot\frac{1}{cos^2x}-2-1\\\\=cosec^2x\cdot sec^2x-3=sec^2x\ cosec^2x-3=R$

3 0

2 years ago

PLEASE HELP!! A tennis ball machine serves a ball vertically into the air from a height of two feet, with an initial speed of 1

ch4aika [34]

Thank you for posting your question here. I hope the answer below will help.

Vo=110 feet per second
ho=2 feet 
So, h(t) = -16t^2 +110t +2 
Take the derivative: h'(t) = 110 -32t 
The maximum height will be at the inflection when the derivative crosses the x-axis aka when h'(t)=0. 
So, set h'(t)=0 and solve for t: 
0 = 110 -32t 
-110 = -32t 
t=3.4375 
t=3.44 seconds

4 0

2 years ago

Read 2 more answers