The reliability of a two-component product if the components are in parallel is 0.99.
In this question,
The probability of failure-free operation of a system with several parallel elements is always higher than that of the best element in the system. Reliability can be increased if the same function is done by two or more elements arranged in parallel.
A system contains two components that are arranged in parallel, they are 0.95 and 0.80.
Therefore the system reliability can be calculated as follows
⇒ 1 - ( 1 - 0.95 ) × ( 1 - 0.80 )
⇒ 1 - (0.05 × 0.20)
⇒ 1 - 0.01
⇒ 0.99
Hence we can conclude that the reliability of a two-component product if the components are in parallel is 0.99.
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Add 20 to complete the square
Answer:
Step-by-step explanation:
60 -1 1/2 (8) 2
= 60 - 3/2 (8)(2)
= 60 - 3(8)
= 60 - 24
= 36
Answer:
-y^4+4y
Step-by-step explanation:
Answer:
1.5 in
Step-by-step explanation:
Let x be the width of the frame.
Side of print=10 in
Area of frame=69 square in
We have to find the width of the frame.
Side of frame=10+x+x=10+2x
Area of square=
By using the formula
Area of print=
Area of frame with print=
Area of frame=Area of frame with print-Area of print
Because Side is always positive.
Hence, width of frame=1.5 in