If we look at the sugar-water phase diagram; at 80° C : 26% of water will dissolve 74% of sugar C = m / ( m + 1000 g ) · 100 74 = m / ( m + 1000 g ) · 100 0.74 = m / ( m + 1000 g ) m = 0.74 · ( m + 1000 g ) m = 0.74 m + 740 g m - 0.74 m = 740 g 0.26 m = 740 g m = 740 g : 0.26 m = 2,846.15 g ≈ 2,846 g Answer: m ( sugar ) = 2,846 g.
The answer is N2 + 3H2 yields 2NH3. The oxidation-reduction reaction means that there is electrons transfer during the reaction which means that the valence changed.