All categories

2 years ago

Help me please with this

Mathematics

2 answers:

Nutka1998 [239]2 years ago

8 0

Answer:

Step-by-step explanation:

Solving the inequality

$\frac{x+3}{6}$ > $\frac{x}{4}$ + 1

Multiply through by 12 ( the LCM of 6 and 4 ) to clear the fractions

2(x + 3) > 3x + 12

2x + 6 > 3x + 12 ( subtract 2x from both sides )

6 > x + 12 ( subtract 12 from both sides )

- 6 > x , that is

x < - 6

The only value less than - 6 is - 10

Thus x = - 10 is a solution to the inequality

Sloan [31]2 years ago

8 0

Your answer is X = -10 I believe

You might be interested in

Point O is the center of the circle in the diagram. What is m∠BCA ?

netineya [11]

The sum of angle around a point equal 360°
so (BOA) = 360-250=110°
and the sum of angle in the shape CAOB = 360°
so BCA = 360-(110+90+90)= 70°
THE ANSWER IS C.70°

7 0

2 years ago

1 1/2 divided by 3 simplify your andwrr

Phantasy [73]

1 1/2 / 3

3/2 / 3

0.5 or 1/2

---

hope it helps

8 0

2 years ago

Read 2 more answers

There are 180 dogs. If 35% of them are huskies, how many huskies are there? *<br> Your answer

raketka [301]

Answer:

The answer is: 63

Step-by-step explanation:

Divide 180 by 35% to find how many are huskies

and its 63.

Check on calculator to make sure: 180 ÷ 35% = 63

3 0

2 years ago

A class has 35 students, of which 16 are male and 19 are female. If 6 of the students are selected at random to form a committee

madreJ [45]

Answer:

The probability of choosing exactly 2 male and 4 female students = $\frac{\binom{16}{2}\times \binom{19}{4}}{\binom{35}{6}}$

Step-by-step explanation:

We are given that a class has 35 students

Number of male=16

Number of female=19

We have to choose 6 students for committee

We have to find the probability that exactly 2 male students are selected

Probability=P(E)= $\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}$

If we have to choose total 6 student in which 2 male and 4 female

Combination formula:

$nC_r=\frac{n!}{r!(n-r)!}$

Using the formula

The probability of choosing exactly 2 male and 4 female students = $\frac{\binom{16}{2}\times \binom{19}{4}}{\binom{35}{6}}$

5 0

2 years ago

Serious inquiries only please and double check ur work please before posting

Darya [45]

To calculate mean: Just add up all the numbers, then divide by how many numbers there are.345 + 673 + 728 +775 + 822 +827 +839 + 951 = 5960/8 = 745
633 + 673 + 728 +775 + 822 +827 +839 + 951 = 6248/8 = 781781- 745 = 35 It increases by 35To find the Median, place the numbers in value order and find the middle. BUT, with an even amount of numbers things are slightly different. In that case we find the middle pair of numbers, and then find the value that is half way between them. This is easily done by adding them together and dividing by two. 345 673 728 775 822 827 839 951 The median = 822-775 /2
The median =23.5After the change633 673 728 775 822 827 839 951 The median = 822-775 /2
The median =23.5The median stays the same.

3 0

2 years ago