Answer:
a) Unsaturated
b) Supersaturated
c) Unsaturated
Explanation:
A saturated solution contains the <u>maximum amount of a solute that will dissolve in a given solvent at a specific temperature</u>.
An unsaturated solution contains <u>less solute than it has the capacity to dissolve. </u>
A supersaturated solution, <u>contains more solute than is present in a saturated solution</u>. Supersaturated solutions are not very stable. In time, some of the solute will come out of a supersaturated solution as crystals.
According to these definitions and considering that the solubility of KCl in 100 mL of H₂O at <u>20 °C is 34 g</u>, and at <u>50 °C is 43 g</u> we can label the solutions:
a) 30 g in 100 mL of H₂O at 20 °C ⇒ unsaturated
b) 65 g in 100 mL of H₂O at 50 °C ⇒ supersaturated
c) 42 g in 100 mL of H₂O at 50 °C and slowly cooling to 20 °C to give a clear solution <u>with no precipitate</u> ⇒ unsaturated (if it were saturated it would have had precipitate)
A. Raccoons. They will be able to survive in a housing area just as well, or even better then they had in the forrest.
I hope that helped! :D
Answer:
d = 9.5× 10⁻⁴ Kg/cm³
Explanation:
Given data:
Length of cube = 1.02 cm
Mass of cube = 0.001012 Kg
Density of cube = ?
Solution:
The length , height and width of cube is always same. Thus the volume of cube is,
Volume = length × height× width
Volume = 1.02 cm × 1.02 cm × 1.02 cm
Volume = 1.06 cm³
Density of cube:
d = 0.001012 Kg /1.06 cm³
d = 9.5× 10⁻⁴ Kg/cm³
Answer:
I would not accept it.
Explanation:
Although it is tempting to accept the janitor's offer and save the scholarship, which is not easy to get, I would not accept his offer, as I do not believe in victories based on dishonesty and would be heavy on conscience if I did the opposite. Obviously, I would not like to lose my scholarship and for that reason, I would look for other ways that would be honest and help me improve my grade. If I could not improve and lose the scholarship, I would be extremely sad, but I would be at peace with my conscience.
Answer:
See explaination
Explanation:
please kindly see attachment for the step by step solution of the given problem