( n + -2 ) x ( n - -4 ) = 27
What are the two n's?
2 answers:
Simplify n + -2 to n - 2
(n - 2)(n + 4) = 27
Expand
n^2 + 4n - 2n - 8 = 27
Simplify n^2 + 4n - 2n - 8 to n^2 + 2n - 8
n^2 + 2n - 8 = 27
Move all terms to one side
n^2 + 2n - 8 - 27 = 0
Simplify n^2 + 2n - 8 - 27 to n^2 + 2n - 35
n^2 + 2n - 35 = 0
Factor n^2 + 2n - 35
(n - 5)(n + 7) = 0
Solve for n
<u>n = 5, -7 </u>
Answer:
9 and 3
Step-by-step explanation:
27/3=9
There are 2 different ways to solve this equation.
Side note: subtracting a negative (4- -3) turns the equation into addition (4+3) and adding a negative (4+ -3) turns the equation into subtraction (4-3)
So the original equation: (n + -2)x(n - -4)=27
Turns into this: (n-2)x(n+4)=27
Way 1: (11-2)x(-1+4)=27
9x3=27
Way 2: (5-2)x(5+4)=27
3x9=27
Hope this helped! :)
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