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2 years ago

Electrons move in what is called an atoms electron _______. Plz help me

1 answer:

5 0

Electrons move in what is called an electron cloud. Each atom has its own electron cloud associated with it. This region simply represents an area or likelihood within that an electron of corresponding energy can be found within.

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Answer all of dem Free BRAINIEST ON THE ROLL

ycow [4]

T, F, T, T, F

Explain:

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2 years ago

Read the Safety Data Sheet of hydrogen peroxide to identify the recommended way to store this substance. Choose one:_______.

Lena [83]

Answer:

The correct option is C.

In a tightly closed container in a dry and well-ventilated place

Explanation:

Hydrogen peroxide should be store in a tight closed container and ventilated area because it is an oxidizing agent and it's has oxidizing characteristics. If to is exposed or the bottle lid is broken and exposed it can react and liberate oxygen and heat. It can react with the air and chemical it is exposed with. This will make it to be less effective and there will be a change in it's composition.

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2 years ago

Why is the chemical symbol for calcium ca

Assoli18 [71]

You are right, it's CA Calcium, 40.08, Group 2 and Row 4.

6 0

3 years ago

1. What element is a metalloid in group 3?

denis23 [38]

Answer:

1.The metalloids; boron (B), silicon (Si), germanium (Ge), arsenic (As), antimony (Sb), tellurium (Te), polonium (Po) and astatine (At) are the elements found along the step like line between metals and non-metals of the periodic table.

2.hydrogen

The elements generally classified as nonmetals include one element in group 1 (hydrogen);

3.element iron

The element iron is in group 8, and therefore has two or three apparent valence electrons.

8 0

2 years ago

The solubility of o2 at 20c is 1.38 x10^-3. the partial presure of o2 in the air at sea level is 0.27 atm. using henery;s law, c

netineya [11]

<u>Answer:</u> The solubility of oxygen at 682 torr is $4.58\times 10^{-3}M$

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{A}=K_H\times p_{A}$

Or,

$\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}$

where,

$C_1\text{ and }p_1$ are the initial concentration and partial pressure of oxygen gas

$C_2\text{ and }p_2$ are the final concentration and partial pressure of oxygen gas

We are given:

Conversion factor used: 1 atm = 760 torr

$C_1=1.38\times 10^{-3}M\\p_1=0.27atm\\C_2=?\\p_2=682torr=0.897atm$

Putting values in above equation, we get:

$\frac{1.38\times 10^{-3}}{C_2}=\frac{0.27atm}{0.897atm}\\\\C_2=\frac{1.38\times 10^{-3}\times 0.897atm}{0.27atm}=4.58\times 10^{-3}M$

Hence, the solubility of oxygen gas at 628 torr is $4.58\times 10^{-3}M$

4 0

2 years ago