2 years ago

What is the sum of the measures of interior angles of a 15-sides polygon

Mathematics

1 answer:

oksano4ka [1.4K]2 years ago

5 0

Using
sum = (n-2)180
= (15-2)180 = 13×180 = 2340°

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Use Gauss's approach to find the following sums (do not use formulas). 1+3+5+7+...999

muminat

$S=1+3+5+\cdots+995+997+999$
$S=999+997+995+\cdots+5+3+1$
$\implies 2S=(1+999)+(3+997)+(5+995)+\cdots+(995+5)+(997+3)+(999+1)$

$2S=\underbrace{1000+1000+\cdots+1000+1000}_{500\text{ times}}$

(We are adding 500 instances of 1000 because that's how many odd numbers there are between 1 and 1000, inclusive.)

$2S=500\times1000=500000$
$\implies S=250000$

4 0

3 years ago

PLZZZ help with this its pretty simple!

zubka84 [21]

Answer:

2x^3−7x^2+16x−15

Step-by-step explanation:

(2x−3)(x^2−2x+5)

=(2x+−3)(x^2+−2x+5)

=(2x)(x^2)+(2x)(−2x)+(2x)(5)+(−3)(x^2)+(−3)(−2x)+(−3)(5)

=2x^3−4x^2+10x−3x^2+6x−15

=2x3−7x2+16x−15