Domain is the input and/or x
Range is the output and/or y
So to find the domain you would look for the x axis in a graphed function, the input on a table, or the numbers in a problem that would be on that axis or side of the table. Same for range
f(3) = 1
substitute x = 3 into f(x)
f(3) = (2 × 3) - 5 = 6 - 5 = 1
Answer:
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Step-by-step explanation:
3, 9, 15, 21, ...
9-3 = 6; 15-9 = 6; 21-15 = 6 ⇒ d = 6
first term: a = 3
difference: d = 6
so the formula:
and:
Answer:
13
Step-by-step explanation:
Here's a method of finding the area of any polygon knowing its vertices. I'm using this parallelogram as an example.
Make a table like this (each vertex with its x- and y-coordinates):
Pt x y
A 3 6
B 6 5
C 5 1
D 2 2
A 3 6
Now multiply each x-coordinate by the y-coordinate on the line below and write it on the right side. Bold type shows the first multiplication.
x y
A 3 6
B 6 5 15
C 5 1 6
D 2 2 10
A 3 6 12
Now multiply each y-coordinate by the x-coordinate on the line below and subtract from each produce you already have. Do each subtraction. Bold type shows the first multiplication.
x y
A 3 6
B 6 5 15 - 36 = -21
C 5 1 6 - 25 = -19
D 2 2 10 - 2 = 8
A 3 6 12 - 6 = 6
Add all the differences.
x y
A 3 6
B 6 5 15 - 36 = -21
C 5 1 6 - 25 = -19
D 2 2 10 - 2 = 8
A 3 6 12 - 6 = 6
+____
-26
The area of the polygon is the absolute value of half of the sum of the differences.
area = |-26/2| = |-13| = 13
Answer:
20 days
Step-by-step explanation:
899- 225= 674
674÷ 35= 19.257....
which you would round it up to 20 because he would have to work the extra day because you need more than less.
