Given :
<span>Triangle fgh is inscribed in circle o
</span>
oh = 6 = radius of the circle
<span>∵ fh is congruent to og
</span>
<span>∴ fh = og = radius og the circle = 6
</span>
<span>∵ of = radius of the circle = 6
</span>
<span>∴ oh = fh = of = radius of the circle = 6
</span>
∴ Δ foh is Equilateral Triangle
<span> </span>∴∠ foh = 60° ⇒⇒⇒ property of <span>the equilateral Triangle
</span>
∵ total area of the circle = π r² and total central angle of the circle = 360°
∴ Area of sector foh = (60°/360°) * π r²
∴ Area of sector foh = (60°/360°) * π * 6² ≈ 18.85
The answer is:
<span>the area of the sector formed by angle foh
= 18.85</span>
<h3>
Answer: x = 29</h3>
========================================================
Work Shown:
A = 2x+3
B = x
angles A and B are complementary, so they add to 90 degrees
A+B = 90
(2x+3)+(x) = 90
2x+3+x = 90
2x+x+3 = 90
3x+3 = 90
3x+3-3 = 90-3
3x = 87
3x/3 = 87/3
x = 29
Extra info:
2x+3 = 2(29)+3 = 58+3 = 61
Note that 29 and 61 add to 29+61 = 90
-3 times (x+8)=-21
-3(x+8)=-21
distributive property=a(b+c)=ab+ac
-3(x+8)=-3x+(-3)(8)=-3x-24
-3x-24=-21
add 3x to both sides
-24=-21+3x
add 21 to both sides
-3=3x
divide both sids by 3
-1=x
x=-1
Answer: 7/13 or about 54%
Explanation: 4+6+3= 13 Only 7 out of these 13 are nonwhite so
Answer:
94.33
Step-by-step explanation:
50 x50 +80 x80 =8900 squared 94.33