The answer to this question is:
A circle is growing so that the radius is increasing at the rate of 2cm/min. How fast is the area of the circle changing at the instant the radius is 10cm? Include units in your answer.?
✔️I assume here the linear scale is changing at the rato of 5cm/min
✔️dR/dt=5(cm/min) (R - is the radius.... yrs, of the circle (not the side)
✔️The rate of area change would be d(pi*R^2)/dt=2pi*R*dR/dt.
✔️At the instant when R=20cm,this rate would be,
✔️2pi*20*5(cm^2/min)=200pi (cm^2/min) or, almost, 628 (cm^2/min)
Hoped This Helped, <span>Cello10
Your Welcome :) </span>
Multiply the factors together. You should get the original expression.
For example, if we are to factor
2x^2 + 4x
we would factor as
2x(x + 2).
Check this by multiplying back in
2x*x + 2x*2 = 2x^2 + 4x
which is what we started with, so we know we are correct.
First we need to find the area of the fence, since paint covers square feet and squared units refers to area. The area of the fence is 26 x 7, which is 182 sq ft. If one gallon of paint will cover 350 sq ft, your proportion will look like this, with gallons of paint on top and square feet on the bottom.
. Cross multiply to get 350x = 182 and x = .52, just a bit over a half of a gallon of paint.
Answer:
Um.. Im not sure about this one.. you're in college?
Step-by-step explanation:
Answer: 20 ft
Step-by-step explanation:
The mirror is set away from the flagpole on the same scale set away from her.
The distance she stand's away from the mirror is 1/4 of the length of the distance between the mirror and the flag pole because she's 1/4 of the flagpole's size.
This means her size x4 is the size for the flag pole. This checks out because 12x4=48
So to find the height we must do 5x4
5x4=20
