Answer:
The graph is sketched by considering the integral. The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.
Step-by-step explanation:
We sketch the integral ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ. We consider the inner integral which ranges from r = 0 to r = 6/cosθ. r = 0 is located at the origin and r = 6/cosθ is located on the line x = 6 (since x = rcosθ here x= 6)extends radially outward from the origin. The outer integral ranges from θ = 0 to θ = π/4. This is a line from the origin that intersects the line x = 6 ( r = 6/cosθ) at y = 1 when θ = π/2 . The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.
9.8t^2-49t+40=0
t=(49±√833)/19.6
t≈1.027, 3.97
1.027<t<3.97
Answer:
Inverse variation
Step-by-step explanation:
Given equation is .
Now we need to identify the type of variation represented by .
We know that there are two type of variations direct and inverse.
If y and x are in direct variation then we write equation as .
where k is the constant of variation.
If y and x are in inverse variation then we write equation as .
Given equation looks similar to .
So that means finala answer is "Inverse variation".
Answer:
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