The statements true about the the function f(x) = 2x2 – x – 6 are-
- The vertex of the function is (one-quarter, negative 6 and one-eighth).
- The function has two x-intercepts.
<h3>What is vertex of parabola?</h3>
The vertex of parabola is the point at the intersection of parabola and its line of symmetry.
Now the given function is,
f(x) = 2x^2 – x – 6
Also, it is given that the vertex is located at (0.25, -6) and the parabola opens up, the function has two x-intercepts.
Comparing the given function with standard form,
f(x) = a x^2 bx + c
By comprison we get,
a = 2
b = -1
c = -6
Now, x-coordinate of vertex is given as,
x = -b/2a
put the values we get,
x = -(-1)/2*2
or, x = 1/4
Put the value of x in given function, so y-coordinate of the vertex is given as,
f(1/4) = 2(1/4)² - 1/4 - 6
= -49/6
= -6 1/8
Hence, The statements true about the the function f(x) = 2x2 – x – 6 are-
- The vertex of the function is (one-quarter, negative 6 and one-eighth).
- The function has two x-intercepts.
More about vertex :
brainly.com/question/86393
#SPJ1
If these are all the side lengths then just multiply all of them together
Answer) 326,400cm^5
Answer: the domain of f(x)=2x+2 is all real numbers and the domain of g(x)=x^2 is (0, infinity)
Step-by-step explanation:
there is no horizontal asymptote given
Answer:
80 is the answer to your question
Answer:
y=-3x+15
Step-by-step explanation:
the midpoint of UV (using the midpoint formula) is (3,6)
the slope of UV= 4/12= (1/3)
perpendicular slope is -3
now find line with slope -3 passing (3,6)
y-6=-3(x-3)
y=-3x+15
