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2 years ago

10

A bag contains 4 red marbles, 3 green marbles, and 2 yellow marbles. The probability of randomly picking a yellow marble is . Wh

at is the probability of not picking a yellow marble?

1 answer:

djverab [1.8K]2 years ago

8 0

You would add the red marbles and green marbles together and which would be 7 the get the total marbles would be 9 so the answer would be 7/9 or 78%

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What is the answer to this question plss and thank you

cluponka [151]

A defines the function

f(1) = - 8 ×( $\frac{5}{2} )^{0}$ = - 8 × 1 = -8

f(2) = - 8 ×( $\frac{5}{2}) ^{1}$ = - $\frac{(8.5)}{2}$ = - 20

f(3) = - 8 ×( $\frac{5}{2}) ^{2}$ = - 8 × $\frac{25}{4}$ = - 50

f(4)= - 8 ×( $\frac{5}{2}) ^{3}$ = - 8 × $\frac{125}{8}$ = -125

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2 years ago

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IgorLugansk [536]

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Step-by-step explanation:

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2 years ago

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chubhunter [2.5K]

Answer:

$\large\boxed{y=3(x-2)^2-8}$

Step-by-step explanation:

The vertex form of an equation of a parabola y = ax² + bx + c:

$f(x)=a(x-h)^2+k$

(h, k) - vertex

$h=\dfrac{-b}{2a},\ k=f(h)$

We have the equation:

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Substitute:

$h=\dfrac{-(-12)}{2(3)}=\dfrac{12}{6}=2\\\\k=f(2)=3(2^2)-12(2)+4=3(4)-24+4=12-24+4=-8$

Finally:

$y=3(x-2)^2+(-8)=3(x-2)^2-8$

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