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2 years ago

How many water molecules are in a block of ice containing 1.75 mol of water (H2O)?

2 answers:

6 0

1.75 mol H2O x (6.022x10^23 molecules H2O / 1 mol H2O) = 1.05x10^24 molecules H2O if you need a further example let me know

Nostrana [21]2 years ago

3 0

Answer: The number of molecules present in the given moles of water are $1.054\times 10^{24}$

Explanation:

We are given:

Moles of water = 1.75 moles

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of molecules.

So, 1.75 moles of water will contain = $1.75\times 6.022\times 10^{23}=1.054\times 10^{24}$ number of molecules.

Hence, the number of molecules present in the given moles of water are $1.054\times 10^{24}$

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Answer:

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2 years ago

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timofeeve [1]

Answer:

$\boxed {\boxed {\sf 0.80 \ mol\ F}}$

Explanation:

We are asked to find how many moles are in 4.8 × 10²³ fluorine atoms. We convert atoms to moles using Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of fluorine.

We will convert using dimensional analysis and set up a ratio using Avogadro's Number.

$\frac {6.022 \times 10^{23} \ atoms \ F}{ 1 \ mol \ F}$

We are converting 4.8 × 10²³ fluorine atoms to moles, so we multiply the ratio by this number.

$4.8 \times 10^{23} \ atoms \ F *\frac {6.022 \times 10^{23} \ atoms \ F}{ 1 \ mol \ F}$

Flip the ratio so the units of atoms of fluorine cancel each other out.

$4.8 \times 10^{23} \ atoms \ F *\frac { 1 \ mol \ F}{6.022 \times 10^{23} \ atoms \ F}$

$4.8 \times 10^{23} *\frac { 1 \ mol \ F}{6.022 \times 10^{23} }$

Condense into 1 fraction.

$\frac { 4.8 \times 10^{23} }{6.022 \times 10^{23} } \ mol \ F$

Divide.

$0.7970773829 \ mol \ F$

The original measurement of atoms has 2 significant figures, so our answer must have the same. For the number we found, that is the hundredths place. The 7 in the thousandths tells us to round the 9 in the hundredths place up to a 0. Then, we also have to round the 7 in the tenths place up to an 8.

$0.80 \ mol \ F$

4.8 × 10²³ fluorine atoms are equal to 0.80 moles of fluorine.

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2 years ago