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3 years ago

Arrange the steps to perform this subtraction operation in the correct order.

Mathematics

2 answers:

taurus [48]3 years ago

7 0

Answer:

=1.23*10^6

Step-by-step explanation:

We have to calculate

(1.93*10^7 )-(9.7*10^6)

In order to add or subtract two numbers in scientific notation, we have to make sure that the power of exponents in both numbers is same.

We have to reduce the power of 10 in first number from 7 to 6

So,

Step 1:

1.93*10^7=1.93*10*10^6

=10.93*10^6

Now,

Step 2:

=(1.93*10^7 )-(9.7*10^6 )

= 10.93*10^6- 9.7*10^6

Step 3:

=(10.93-9.7)*10^6

=1.23*10^6

Andrej [43]3 years ago

7 0

Answer with explanation:

W have to find the value of :

$[A=1.93 \times 10^7] - [B=9.7 \times 10^6]$

Here exponent of 10 differs in both of these terms. So, to find the difference of A and B, we should make exponent of 10 equal in both the terms.

Exponent of A is Higher,so we will try to make this equal to exponent of 10 in B.

$A=1.93 \times 10^7\\\\A=19.3 \times 10^6\\\\A-B=19.3 \times 10^6-9.7 \times 10^6\\\\=(19.3-9.7) \times 10^6\\\\=9.6\times 10^6$

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(d) Jim walks three miles in 45 minutes. How long does it take for him to walk 5 miles?

kramer

Answer:

5 miles = 75 minutes

Step-by-step explanation:

We know that:

3 miles = 45 minutes

Solution:

3 miles = 45 minutes
=> 1 mile = 45/3 minutes
=> 5 miles = 45/3 x 5
=> 5 miles = 15 x 5
=> 5 miles = 75 minutes

Hence, it takes 75 minutes for Jim to walk 5 miles.

6 0

1 year ago

(a) The function k is defined by k(x)=f(x)g(x). Find k′(0).

Brut [27]

Answer:

(a) k'(0) = f'(0)g(0) + f(0)g'(0)

(b) m'(5) = $\frac{f'(5)g(5) - f(5)g'(5)}{2g^{2}(5) }$

Step-by-step explanation:

(a) Since k(x) is a function of two functions f(x) and g(x) [ k(x)=f(x)g(x) ], so for differentiating k(x) we need to use product rule,i.e., $\frac{\mathrm{d} [f(x)\times g(x)]}{\mathrm{d} x}=\frac{\mathrm{d} f(x)}{\mathrm{d} x}\times g(x) + f(x)\times\frac{\mathrm{d} g(x)}{\mathrm{d} x}$

this will give k'(x)=f'(x)g(x) + f(x)g'(x)

on substituting the value x=0, we will get the value of k'(0)

{for expressing the value in terms of numbers first we need to know the value of f(0), g(0), f'(0) and g'(0) in terms of numbers}{If f(0)=0 and g(0)=0, and f'(0) and g'(0) exists then k'(0)=0}

(b) m(x) is a function of two functions f(x) and g(x) [ $m(x)=\frac{1}{2}\times\frac{f(x)}{g(x)}$ ]. Since m(x) has a function g(x) in the denominator so we need to use division rule to differentiate m(x). Division rule is as follows : $\frac{\mathrm{d} \frac{f(x)}{g(x)}}{\mathrm{d} x}=\frac{\frac{\mathrm{d} f(x)}{\mathrm{d} x}\times g(x) + f(x)\times\frac{\mathrm{d} g(x)}{\mathrm{d} x}}{g^{2}(x)}$