Answer:
1813.137 KJ
Step-by-step explanation:
potential energy of the body = mgH
where m is mass in Kg , g= 9.81 m/sec^2 and H= height in m
here m= 1000 kg, g= 9.81 m/s^2 and H= 607 feet = 607×0.305= 185.135 m
hence the potential energy p= 1000×9.81×185.135= 1813137.2 J
= 1813.137 KJ
hence the potential energy associated with 1 m^3 of water at 607 feet tall taking the mass as 1000 kg is = 1813.137 KJ
Answer:
D.(2,0) and (0,-4)
Step-by-step explanation:
A P E X approved.
Okay, to find length CE, your going to know the value of x. Length BC + CE = BD + DE.3x+47+x+26=27+x+10Simplify the equation to get4x+73=37+xyou can choose one of four ways to continue, but I will choose to subtract x3x+73=37Subtract 73 from both sides of the equal sign3x=-36divide by 3 on both sides of the equal sign to get the value of xx=-12Now, plug in -12 for x in length CE to get -12+26=14
69% ............................is the answer to your question