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2 years ago

Which way does the friction arrow go in a free body diagram for a moving object point

Physics

2 answers:

True [87]2 years ago

7 0

Answer:

Frictional force opposes relative motion between surfaces

Explanation:

Friction that exists when the object is not moving is called static friction. In static friction ,If we are applying a force in the object the frictional force is in the opposite direction . If it is not the case, there have been some net force and the object starts accelarating.

The main component of the contact force of two objects is normal force and that is in the perpendicular direction. Frictional force is other complnent. This frictional force is parallel to the interface between objects. Frictional force opposes relative motion between surfaces.

Oliga [24]2 years ago

7 0

Answer:

Frictional force opposes relative motion between surfaces

Explanation:

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Transformer is used in rectifier step up and step down voltage?<br>

tensa zangetsu [6.8K]

Answer:

While the use of the type of transformer in a rectifier depends on the voltage requirement or to meet desired operating conditions, a step-down transformer is used mainly to reduce the voltage. It is used to bring the high AC voltage level to a reasonable value or the desired output voltage.

Explanation:

Hope it helps

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1 year ago

We would be more likely to get an accurate measurement of the distance from Earth to a nearby star if we took the angular measur

NeTakaya

Answer:

6 month interval

Explanation:

The distance to a nearby star in theory is more simple than

one might think! First we must learn about the parallax effect. This is the mechanism our eyes use to perceive things at a distance! When we look at the star from the earth we see it at different angles throughout the earth's movement around the sun similar to how we see when we cover on eye at a time. Modern telescopes and technology can help calculate the angle of the star to the earth with just two measurements (attached photo!) Since we know the distance of the earth from the sun we can use a simple trigonometric function to calculate the distance to the star. The two measurements needed to calculate the angle of the star to the earth caused by parallax (in short angle θ) are shown in the second attached photo.

So using a simple trigonometric function $Sin\theta=\frac{r}{d}$ we can solve for d which is the distance of the earth to the star:

$d=\frac{r}{Sin\theta}$

In the first attached photo a picture where r is the distance to the star and the base of the triangle is the diameter of the earth.

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2 years ago

Which of following is an example of deduction?

Jobisdone [24]

A, because Antoine came to a conclusion that it must have rained based on his visuals.

6 0

2 years ago

Water is leaking out of an inverted conical tank at a rate of 10,500 cm3/min at the same time that water is being pumped into th

satela [25.4K]

The tank has a volume of $\dfrac\pi3R^2H$ , where $H=6\,\rm m$ is its height and $R=\dfrac d2=2\,\rm m$ is its radius.

At any point, the water filling the tank and the tank itself form a pair of similar triangles (see the attached picture) from which we obtain the following relationship:

$\dfrac26=\dfrac rh\implies r=\dfrac h3$

The volume of water in the tank at any given time is

$V=\dfrac\pi3r^2h$

and can be expressed as a function of the water level alone:

$V=\dfrac\pi3\left(\frac h3\right)^2h=\dfrac\pi{27}h^3$

Implicity differentiating both sides with respect to time $t$ gives

$\dfrac{\mathrm dV}{\mathrm dt}=\dfrac\pi9h^2\,\dfrac{\mathrm dh}{\mathrm dt}$

We're told the water level rises at a rate of $\dfrac{\mathrm dh}{\mathrm dt}=20\,\frac{\rm cm}{\rm min}$ at the time when the water level is $h=2\,\mathrm m=200\,\mathrm{cm}$ , so the net change in the volume of water $\dfrac{\mathrm dV}{\mathrm dt}$ can be computed:

$\dfrac{\mathrm dV}{\mathrm dt}=\dfrac\pi9(200\,\mathrm{cm})^2\left(20\,\dfrac{\rm cm}{\rm min}\right)=\dfrac{800,000\pi}9\,\dfrac{\mathrm{cm}^3}{\rm min}$