Below is the solution:
There are two equations to be solved here. The first one we assign variables to the home runs Peter hits, P, and Alice hits, A. P=2*(A-6) The second equation is the sum of both players home runs.P + A = 18Solving for P yieldsP=18-A We substitute the solution for P into the first equation and solve for A.(18-A) = 2*(A-6)18 - A = 2A - 123A = 30A = 10 Now that A is known, we can plug it into either equations for P to find how many home runs Peter hitsP=18 - (10) = 8orP=2((10)-4) = 8
Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
0 or dot, depending on what course you are taking
