Evaluate the geometric series. Round to the nearest hundredth. Please help ASAP!!!

Mathematics

1 answer:

lana [24]2 years ago

4 0

Answer:

Rounded to the nearest hundredth, the answer is 10.67.

Step-by-step explanation:

To obtain this answer, you have to take the summation from n=1 to n=10 of $8(\frac{1}{4})^{n-1}$ by plugging in n=1 into the equation, then n=2, so on and so forth, all the way up to n=10, and adding those all together. Done by hand, this would look like:

$8(\frac{1}{4})^{1-1}+8(\frac{1}{4})^{2-1}+8(\frac{1}{4})^{3-1}+8(\frac{1}{4})^{4-1}+8(\frac{1}{4})^{5-1}+8(\frac{1}{4})^{6-1}+8(\frac{1}{4})^{7-1}+8(\frac{1}{4})^{8-1}+8(\frac{1}{4})^{9-1}+8(\frac{1}{4})^{10-1}=(approximately) 10.67$

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Water level in a well was 20m below ground level. During rainy season, rainwater collected in different water tanks was drained

IgorC [24]

Answer:

17 m

Step-by-step explanation:

As shown in the figure, $A_0-B_0$ is the ground level, $A_1-B_1$ is the old level of water which was at 20 m below ground level, $A_2-B_2$ is the new level of water which is 5m above of old level. The height of wall of the well, 1.20 m, and the the pelly at 80 cm =0.80 m, has been shown too.