Answer:
20 different total voting combinations.
Step-by-step explanation:
so lets called them A, B, C, D, and E
If John has to vote on his favorite and second favorite that means we will be selecting 2 bands out of the 5 possible to choose from.
To find the TOTAL amount of different combinations we need to pair up bands and find all the combo's.
Here are the results/totals:
AB
AC
AD
AE
BA
BC
BD
BE
CA
CB
CD
CE
DA
DB
DC
DE
EA
EB
EC
ED
If you want to do it simpler without listing you can take the the 5 bands and multiple by 4 since you know each initial band (A, B, C, D, and E) will be paired with another band other than itself.
The given function : h(x) = 6 - x
We know that for any functions f(x) and g(x)
f*g (x)=f(x)\times g(x)
Therefore , h*h (x)=h(x)\times h(x)
h*h (x)=(6-x)(6-x)=(6-x)^2
h*h (x)=(6)^2-2(6)(x)+x^2 [ Using identity (a-b)^2=a^2+2ab+b^2 ]
h*h (x)=36-12(x)+x^2
\-------->\ h*h (x)=36-12(x)+x^2 Now, at x= 10 , we get
h*h (10)=36-12(10)+(10)^2
h*h (10)=36-120+100=36+100-120=136-120=16
Hence, the value of (h*h)(10) = 16
hoped it helped
1/2 - 5/13 = 3/26 = 0.115
Because: 1/2 - 5/13 = 1 x 13 ÷ 2 x 13 - 5 x 2 ÷ 13 x 2 = 13/26 - 10/26
13/26 - 10/26 = 13 - 10 ÷26 = 3/26 or 0.115.
Hope helps-Aparri
In order to figure this out, you must solve the equation.
1-6x=7 (given)
-6x=6 (subtract 1 from both sides)
X=-1 (divide both sides by -6)
The answer is no.