Answer:
1) 1.31 m/s2
2) 20.92 N
3) 8.53 m/s2
4) 1.76 m/s2
5) -8.53 m/s2
Explanation:
1) As the box does not slide, the acceleration of the box (relative to ground) is the same as acceleration of the truck, which goes from 0 to 17m/s in 13 s
2)According to Newton 2nd law, the static frictional force that acting on the box (so it goes along with the truck), is the product of its mass and acceleration
3) Let g = 9.81 m/s2. The maximum static friction that can hold the box is the product of its static coefficient and the normal force.
So the maximum acceleration on the block is
4)As the box slides, it is now subjected to kinetic friction, which is
So if the acceleration of the truck it at the point where the box starts to slide, the force that acting on it must be at 136.6 N too. So the horizontal net force would be 136.6 - 108.3 = 28.25N. And the acceleration is
28.25 / 16 = 1.76 m/s2
5) Same as number 3), the maximum deceleration the truck can have without the box sliding is -8.53 m/s2
Answer:
Explanation:
Given
object of mass m is suspended from spring and set in oscillation with time Period T
We know Time period of a mass in oscillation is given by
where k=spring constant
When mass m is replaced by a mass of 2 m time period is given by
i.e. New time period becomes times of previous one
I don't understand the question but impulse and momentum is the same. So maybe is the force same too
Answer:
The coefficient of performance for the cycle is 2.33.
Explanation:
Given that,
Output energy
Work done
We need to calculate the coefficient of performance
Using formula of the coefficient of performance
We need to calculate the
Put the value into the formula
Now put the value of into the formula of COP
Hence, The coefficient of performance for the cycle is 2.33.
The answer would most likely be A since obviously gravity weighs things down which helps the every other masses stay settled in place