Ch3cooh (acetic acid) can form hydrogen bonds between its molecules. based on the lewis structure shown below, how many hydrogen
bond donor and acceptor atoms does this molecule have?
1 answer:
Answer:
Number of Hydrogen Bond Acceptor atoms = 2
Number of Hydrogen Bond Donor atoms = 1
Explanation:
Hydrogen bond interactions are formed between those molecules which contains partial positive hydrogen atoms bonded covalently to most electronegative atoms like Oxygen, Nitrogen and Fluorine.
When hydrogen is attached to Oxygen, Nitrogen or Fluorine its electron density decreases and gets partial positive charge, this partial positive charged hydrogen atom then makes hydrogen bonding with the most electronegative element (partial negative) of neighbor molecule.
In Acetic acid there are two oxygen atoms hence there are two most electronegative elements therefore, two Hydrogen Bond Acceptor atom and each oxygen atom can accept two hydrogen bonds.
Also, it contains only one Hydrogen atom attached to oxygen atom so it has one Hydrogen Bond Donor atom.
Number of Hydrogen Bond Acceptor atoms = 2
Number of Hydrogen Bond Donor atoms = 1
Explanation:
Hydrogen bond interactions are formed between those molecules which contains partial positive hydrogen atoms bonded covalently to most electronegative atoms like Oxygen, Nitrogen and Fluorine.
When hydrogen is attached to Oxygen, Nitrogen or Fluorine its electron density decreases and gets partial positive charge, this partial positive charged hydrogen atom then makes hydrogen bonding with the most electronegative element (partial negative) of neighbor molecule.
In Acetic acid there are two oxygen atoms hence there are two most electronegative elements therefore, two Hydrogen Bond Acceptor atom and each oxygen atom can accept two hydrogen bonds.
Also, it contains only one Hydrogen atom attached to oxygen atom so it has one Hydrogen Bond Donor atom.
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Answer:
see explanation below
Explanation:
You are missing the reaction scheme, but in picture 1, I found a question very similar to this, and after look into some other pages, I found the same scheme reaction, so I'm gonna work on this one, to show you how to solve it. Hopefully it will be the one you are asking.
According to the reaction scheme, in the first step we have NaNH2/NH3(l). This reactant is used to substract the most acidic hydrogen in the alkine there. In this case, it will substract the hydrogen from the carbon in the triple bond leaving something like this:
R: cyclopentane
R - C ≡ C (-)
Now, in the second step, this new product will experiment a SN2 reaction, and will attack to the CH3 - I forming another alkine as follow:
R - C ≡ C - CH3
Finally in the last step, Na in NH3 are reactants to promvove the hydrogenation of alkines. In this case, it will undergo hydrogenation in the triple bond and will form an alkene:
R - CH = CH - CH3
In picture 2, you have the reaction and mechanism.
