- <u>Distance </u><u>between </u><u>the </u><u>house </u><u>and </u><u>tower </u><u>is </u><u>3</u><u>5</u><u> </u><u>m</u>
- <u>The </u><u>height </u><u>of </u><u>the </u><u>tower </u><u>is </u><u>6</u><u>0</u><u> </u><u>m </u>
- <u>The </u><u>height </u><u>of </u><u>the </u><u>house </u><u>is </u><u>2</u><u>5</u><u> </u><u>m</u>
- <u> </u><u>Height</u><u> </u><u>of </u><u>the </u><u>house </u><u>is</u><u> </u><u>2</u><u>5</u><u>m</u>
<u>Therefore</u><u>, </u>
<u>Now</u><u>, </u><u> </u><u>In </u><u>Right </u><u>angled </u><u>ABC</u>
Answer: 36 hotdogs
Step-by-step explanation: You need to find the least common multiple of 9 and 12.
You can check by multiplying 9 and 12 by consecutive whole numbers until you find a number that they match.
Example:
9*1= 9 , 9*2=18, 9*3= 27, 9*4=36, 9*5=45
12*1=12, 12*2=24, 12*3 =36
They both share 36.
This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
Answer:
Step-by-step explanation:
x²+y²=r²
r²=12
r=√12=2√3