Please help with these two questions thank you.

Mathematics

1 answer:

prohojiy [21]2 years ago

6 0

1. Perpendicular Transverse Theorem
2. a=30 and b=60

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Apply your knowledge of square roots to solve equations involving them. Show your step-by-step solution. Remember, each problem

Elena L [17]

Remember to include the positive and negative roots

(7x-2)^2=256
sqrt both sides
7x-2=+/-16
add 2 to both sides
7x=2+/-16
divdide both sides by 7
x=(2+/-16)/7)

x=(2+16)/7=18/7=2 and 4/7
x=(2-16)/7=-14/7=-2

x=2 and 4/7 or -2

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2 years ago

Log 48 is equal to ?

lesya [120]

Answer:

The result can be shown in multiple forms.

Exact Form:

log (48)

Decimal Form:

1.68124123…

Step-by-step explanation:

A multiple of a number is the product of that number and any other whole number. Zero is a multiple of every number.

8 0

2 years ago

Read 2 more answers

Does anyone know how to do this?

krok68 [10]

Answer:

D = 36 - 4 * 9 *(-2) = 104

Step-by-step explanation:

$\sqrt{26 \times 4}$

That's 2 that shet 26

x1= -{-6} - 2 that shet 26/6 x2=-{6}+ 2 that shet 26/6

6 0

2 years ago

How am I supposed to figure this out if csc Theta(0) has a radical number on the top?

Harman [31]

$\bf csc(\theta)=\cfrac{hypotenuse}{opposite}\implies csc(\theta)=\cfrac{\sqrt{7}}{2}\cfrac{\leftarrow hypotenuse=c}{\leftarrow opposite=b}\\\\
-----------------------------\\\\
\textit{so hmm using the pythagorean theorem, we can say that}\\\\
c^2=a^2+b^2\implies \pm \sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
b=opposite\\
a=adjacent
\end{cases}\\\\
\textit{we'll assume is the + of the root, since you're not}\\
\textit{given further info on it, that means the I quadrant}\\\\
$

$\bf -----------------------------\\\\
cos(\theta)=\cfrac{a}{c}\qquad sec(\theta)=\cfrac{c}{a}\qquad tan(\theta)=\cfrac{b}{a}\qquad cot(\theta)\cfrac{a}{b}
$

so just find the "adjacent" side, using the pythagorean theorem, and even though the square root can give you +/-, use the positive one, assuming the angle is in the 1st quadrant

keeping in mind, that the 2nd quadrant is feasible as well, since the opposite side of +2 can also be in the 2nd quadrant

but anyhow, use the I quadrant

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2 years ago

Give the slope between the points<br> (2,5) (14,-4)

andrezito [222]

Answer:

$-\frac{3}{4}$