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2 years ago

Who made. Accurate atomic weight determination’s

1 answer:

6 0

Theodore Richards; first scienstist to recieve nobel prize in Chemistry, earning the award "in recognition of his exact determinations of atomic weights of a large number of chemical elements."

You might be interested in

Which chemical equations show an oxidation- reduction reaction

saveliy_v [14]

Answer:

O2 + 2H2 → 2H2O MgSO4 + CaCl2 → MgCl2 + CaSO4 2Al + 6HI → 2AlI3 + 3H2 FeCl2 + Na2CO3 → FeCO3 + 2NaCl 2AgNO3 + Na2S → Ag2S + 2NaNO3

4 0

1 year ago

How do you find the metal “M”

Elodia [21]

M = Sr (strontium)

Step 1. Calculate the moles of CO_2.

Moles of CO_2 = 0.395 g CO_2 × (1 mol CO_2/44.01 g CO_2)

= 0.008 975 mol CO_2

Step 2. Calculate the moles of MCO_3.

Moles of MCO_3 = 0.008 975 mol CO_2 × (1 mol MCO_3/1 mol CO_2)

= 0.008 975 mol MCO_3

Step 3. Calculate the molar mass of MCO_3

MM = grams/moles = 1.324 g/0.008 75 mol = 147.5 g/mol

Step 4. Calculate the atomic mass of M

M_r = x + 12.01 + 3×16.00 = x + 60.01 = 147.5

x = 147.5 – 60.01 = 87.5

Step 5. Identify M.

The element with the closest atomic mass is Sr (A_r = 87.6).

∴ M = Sr and the compound is SrCO_3.

5 0

3 years ago

The Ksp of silver bromide at 25°C (298 K) is 5.0 x 10-13. Write the solubility expression hydrogen oxygen for this compound and

Rufina [12.5K]

AgBr(s) <—> Ag+(aq) + Br-(aq)

Ksp = [Ag+][Br-]

5 0

2 years ago

If 725 ml of N² gas is at 1 atm, what volume will it have at 1.4 atm?

alexdok [17]

Answer:

518 mL

Explanation:

We can solve this using Boyle's Law Formula

P1V1 = P2V2

where p1 = initial pressure, p2 = final pressure, v1 = initial volume and v2 = final volume

here , the initial pressure is 1 atm and the initial volume is 725mL

we are given the final pressure 1.4 and we need to find the final volume

so we have p1v1 = p2v2

==> plug in p1 = 1 , v1 = 725 mL and p2 = 1.4

(1)(725) = (1.4)v2

==> multiply 1 and 725

725 = (1.4)(v2)

==> divide both sides by 1.4

v2 = 518

N2 would have a volume of 518mL at 1.4atm

7 0

1 year ago

Read 2 more answers

When light is shown on a mixture of chlorine and chloromethane, carbon tetrachloride is one of the components of the final react

velikii [3]

A free-radical substitution reaction is likely to be responsible for the observations. The reaction mechanism of a reaction like this can be grouped into three phases:

Initiation; the "light" on the mixture deliver sufficient amount of energy such that the halogen molecules undergo homologous fission. It typically takes ultraviolet radiation to initiate fissions of the bonds.
Propagation; free radicals react with molecules to produce new free radicals and molecules.
Termination; two free radicals combine and form covalent bonds to produce stable molecules. Note that it is possible for two carbon-containing free-radicals to combine, leading to the production of trace amounts of long carbon chains in the product.

Initiation

$\text{Cl}-\text{Cl} \stackrel{\text{UV}}{\to} \text{Cl}\bullet + \bullet\text{Cl}$