Answer:
60, 75
150 165
240 255
330 345
Step-by-step explanation:
csc 4 theta = -2 sqrt(3)/3
Write in terms of sin
1/ sin (4 theta) = -2 sqrt(3)/3
Using cross products
-2 sqrt(3) = 3 sin (4 theta)
Divide each side by 3
-2 sqrt(3)/3 = sin (4 theta)
Take the inverse sin on each side
sin ^ -1(-2 sqrt(3)/3) = sin ^ -1 (sin (4 theta))
240 +360n = 4 theta
and 300 +360n = 4 theta where n is an integer
Dividing each side by 4
240/4 +360n/4 = 4/4 theta and 300/4 +360n/4 = 4/4 theta
60 + 90n = theta and 75 +90n = theta
We want all the values between 0 and 360
Let n=0
60, 75
n=1
60+90=150 and 75+90 =165
n=2
60+180= 240 75+180=255
n=3
60+270 = 330 75+ 270 =345
Answer: OPTION B.
Step-by-step explanation:
Given the endpoints of the diameter of the circle, we need to find the midpoint, which is the center of the circle.
The following formula is used to calculate the Midpoint:
Given the endpoints of the diameter of the circle:
We can identify that:
Then, we can substitute these values into the formula:
Therefore, the center of the circle is: 
The triangles are ACD and XYZ
Congruent segments means that they have the same length.
Then CD = XY, AC = ZX and AD = ZY
This is the option B. from the list.
Answer :<span>B.CD=XY,DA=YZ,AC=ZX</span>
